Moon Mi trovo così:
\left\{\left[\left(\frac{2}{5}\right)^{-2}+\frac{5}{2}\right]\left(\frac{5}{2}\right)^{-4}+\left(-\frac{2}{5}\right)^{2}:\left(\frac{2}{5}\right)^{-1}\right\}^{-1}=\\
\left\{\left[\left(\frac{5}{2}\right)^{2}+\frac{5}{2}\right]\left(\frac{5}{2}\right)^{-4}+\left(\frac{2}{5}\right)^{2}:\left(\frac{2}{5}\right)^{-1}\right\}^{-1}=\\
\left\{\left[\frac{25}{4}+\frac{5}{2}\right]\left(\frac{5}{2}\right)^{-4}+\left(\frac{2}{5}\right)^3\right\}^{-1}=\\
\left\{\left[\frac{35}{4}\right]\left(\frac{2}{5}\right)^4+\left(\frac{2}{5}\right)^3\right\}^{-1}=\\
\left\{\left[\frac{5*7}{2^2}\right]\left(\frac{2}{5}\right)^4+\left(\frac{2}{5}\right)^3\right\}^{-1}=\\
\left\{\left(\frac{7*2^2}{5^3}\right)+\left(\frac{2}{5}\right)^3\right\}^{-1}=\\
\left\{\left(\frac{28}{5^3}\right)+\left(\frac{2}{5}\right)^3\right\}^{-1}=\\
\left\{\frac{28+8}{125}\right\}^{-1}=\\
\left\{\frac{36}{125}\right\}^{-1}=\frac{125}{36}\\
Magari, dammi conferma per dirmi se ti trovi, può capitare che per la fretta mi perdi qualcosa...
